S_{medzikružie}=π(r_1^{2}-r_2^{2})

r_1

r_1

r_2

\frac{1}{2}\left|XY\right|=\sqrt{r_1^2-r_2^2}    \; \; ... \;   \text{polomer kružnice }k_3

k_3

S_{k_3}= π (r_1^2-r_2^2)

Obsahy sa rovnajú.

S_k_r_u_h_o_v_ý_o_d_s_e_k=πr_1^2·\frac{2·cos\frac{r_2}{r_1}}{360}-r_2·\sqrt{r_1^2-r_2^2}

S_k_r_u_h_o_v_y_o_d_s_e_k=πr_1^2·\frac{2·cos\frac{r_2}{r_1}}{360}-r_2·\sqrt{\frac{S_m_e_d_z_i_k_r_u_z_i_e}{π}}

α=cos\frac{r_2}{r_1}

S = (0, 0)
B = (0, -4)
k_2 = Circle(S, B)
r_2 = Segment(S, B)
C = (10, 0)
k_1 = Circle(S, C)
r_1 = Segment(S, C)
D = Point(k_2)
f = Tangent(D, k_2)
X, Y = Intersect(k_1, f)
g = Segment(Y, X)
r = Segment(X, S)
s = Segment(Y, S)
α = Angle(X, S, Y)
j = Segment(S, D)
c = Circle(D, X)
k_3 = Circle(D, X)